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I know that somehow I am supposed to be able to factor this, but I'm having trouble doing so, and am stuck with a TI-82 that isn't very much help, either. Could someone please show me how to do this by hand?

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- Thread starter MattsAli1108
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- #1

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I know that somehow I am supposed to be able to factor this, but I'm having trouble doing so, and am stuck with a TI-82 that isn't very much help, either. Could someone please show me how to do this by hand?

- #2

marcusl

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EDIT: Sorry, I was blind to the answer. mathwonk has it right in the next post...

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- #3

mathwonk

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- #4

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did you write the question correctly?(X^4-15X^3+32X+372X-1440)/X^2-X-30 as X approaches 6

is the third term in the numerator [itex]32x^2[/itex]?

then it becomes

[tex]\frac{x^4-15x^3+32x^2+372x-1440}{x^2-x-30}=\frac{(x+5)(x-8)(x-6)^2}{(x+5)(x-6)}=(x-8)(x-6)[/tex]

and this approaches 0 as x approaches 6.

- #5

Gib Z

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I would have a feeling you assumption is correct, murshid. Nice work

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Thank you so much for your help!! All of you! It is very much apprecitated!

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Just offering an alternative.

--Stuart Anderson

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